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LINEAR ALGEBRA THEOREMS
A homogeneous system of m equations in n variables either has a unique solution (zero solution) or has infinitely many solutions, depending on whether the number of leading 1s in the reduced row-echelon form is equal to n or is less than n (unique where 1s = n)
Assuming that the sizes of the matrices are such that the indicated operations can be performed the following rules hold: -
A + B = B + A - Commutativity of matrix addition
A + (B+C) = (A+B) + C - Associativity of matrix addition
AB ≠ BA
A(BC) = (AB)C
A(B+C) = AB + AC (A+B)C = AC + BC
a(B+C) = aB + aC
(a+b)C = aC + bC
(ab)C = abC
a(BC) = (aB)C = B(aC)
where A, B, C are matrices and a, b, c are scalars
Assuming the size of the matrices are such that the following operations can be performed: -
Add zero A + 0 = 0 + A = A
Subtracting A A = 0
Multiplying A0 = 0, 0A = 0
Every system of linear equations has either no solution (lines are parallel), exactly one solution (lines all cross in same place), or infinitely many solutions (same line)
If A is invertible then A has a UNIQUE inverse, A-1 and the determinant of A ≠ 0
If A, B are invertible matrices of the same size then AB is invertible with inverse B-1A-1 an extension of this is A1.Ak are invertible and the same size then (A1.Ak) is invertible with inverse (A-1k.A-11)
If A is a square matrix and k, l are positive integers then
Ak.Al = Ak+l
(Ak) l = Akl
If A is invertible then: -
A-1 is invertible and (A-1) -1 = A
An is invertible and (An) -1 = (A-1) n = A-n
For any non-zero scalar k, then (kA) is invertible and (kA) -1 = 1/k A-1
Multiplying ith row of A by C is equivalent to multiplying matrix A on the left by the matrix obtained by multiplying the ith row of I by c. Interchanging rows i and j of A is equivalent to multiplying A on the left by the matrix obtained by interchanging the ith and jth rows of I. Adding a multiple c of the ith row of A to the jth row of A is equivalent to multiplying A on the left by the matrix obtained by adding c ith row of I to jth row of I.
Every elementary matrix is invertible and the inverse is also an elementary matrix
If A is a square nn matrix then the following are equivalent: -
a) A is invertible
b) AX = 0 has only the zero solution
c) The reduced row echelon form of A is In
If A is an invertible nn matrix then for each n1 matrix B, the system of equations AX = B has exactly one solution, namely X = A-1 B
Let A be a square matrix, if B is a square matrix satisfying BA = I then A is invertible and B=A-1 (same applies if AB = I)
(recall theorem 1.11) The following are equivalent: -
a) A is invertible
d) AX=B is consistent for every n1 matrix B
If u, v, w are vectors in 2 space or 3 space and k and l are real scalars then the following rules apply: -
a) u + v = v + u
b) (u+v) + w = u + (v+w)
c) u + 0 = 0 + u = u by definition
d) u + (-u) = 0
e) k(lu) = (kl)u
f) k(u+v) = ku + kv
g) (k+l)u = ku + lu
h) 1. u = u
If u and v are vectors in 2 or 3 space then u.v = ||u|| ||v|| cos θ
If u and v are vectors then v.v = ||v|| and the angle between u and v is acute iff u.v>0, obtuse iff u.v < 0 and π/2 iff u.v=0
If u and v are vectors and k is a real scalar then: -
a) u v = v. u
b) u (v+w) = u.v + u.w
c) k(u.v) = (ku).v = u .(kv)
d) v.v = 0 unless v = 0
If u, a are non-zero vectors then proja u) = (u.a)/ ||a|| . a
The basic rules of vector arithmetic in Rn: -
a) u + v = v + u
b) (u+v) + w = u + (v+w)
c) u + 0 = 0 + u = u
d) u + (-u) = 0
e) k(lu)= (kl)u
f) k(u+v) = ku + kv
g) (k+l)u = ku + lu
h) 1.u = u
Same as 2.4
Let V be a vector space and u is a vector in V and k a scalar then: -
a) 0.u = 0
b) k0 = 0
c) (-1)u = -u
d) if ku=0 then k = 0 or u = 0
If W is a non-empty subset of V then W is a subspace iff: -
a) u and v are in W, then u + v is also in W
b) if k is a scalar, then ku is in W
If v1,.,vr are vectors in vector space V then the set of all linear combinations of v1,.,vr is a subspace of V, called W
A set S with two or more vectors is: -
a) Linearly dependent iff one of the vectors in S is expressible as a linear combination of the others
b) Linearly independent iff no vector in S is expressible as a linear combination of the other vectors in S
Let S = be a set of vectors in Rm. If n>m then S is linearly dependent
If S = is a basis for V then every set with more than n vectors is linearly dependent
Any two basis for a finite dimensional vector space V has the same number of vectors
a) If S = is linearly independent in an n-dimensional vector space V, then S is a basis for V
b) If S = is a spanning set for a n-dimensional vector space V, then S is a basis for V
c) If S = is a linearly independent set in a n-dimensional vector space, V, r<n then S can be enlarged to a basis of V
Elementary row operations do not change the row space of a matrix
The non-zero row vectors in the (reduced) row echelon form of A form a basis for the row space of A
If A is any matrix, then the row space of A and the column space of A have the same dimension
(look at 1.14) If A is an nn matrix, the following are equivalent: -
a) A is invertible
b) AX=0 has only the trivial solution (i.e. the null space of A is )
c) A is row equivalent to the identity
d) AX = b is consistent for every n1 matrix b
e) A has rank n
f) The row vectors of A are linearly independent
g) The column vectors of A are linearly independent
If S = is a basis for a vector space V, then every vector in V can be expressed uniquely as a linear combination of the vectors in S
If P is a transition matrix from a basis B to a basis B then P is invertible and P-1 is the transition matrix from B to B [v]B = P-1 [v]B
If T:V to W is a linear transformation: -
a) T0 = 0
b) T(-v) = -T(v)
If T:V to W is a linear transformation then: -
a) ker(T) is a subspace of V
b) im(T) is a subspace of W
If T:V to W is a linear transformation from an n-dimensional vector space to a vector space W then rank(T) + nullity(T) = n
If T:Rn to Rm is a linear transformation and if is the standard basis for Rn then T is given by multiplication by A, where A is the matrix whose successive columns are Te1,.,Ten
Let T:V to V be a linear transformation on a finite dimensional vector space V. If A is the matrix of T w.r.t some basis B and A is the matrix of T w.r.t a basis B then A = P-1AP where P is the transition matrix from B to B
Let T1:U to V and T2:V to W be linear transformations. Let B, B, B be bases of U, V, W respectively. If A denotes the matrix for T1 w.r.t B and B and C denotes the matrix for T2 w.r.t Band B then CA is the matrix for T2 ˚ T1 w.r.t B and B
Suppose D: Mnn(R) to R is alternating. Then if A is a matrix with two identical rows then D(A) = 0
Suppose D is a determinant function. Let B be a matrix obtained from A by performing an elementary row operation of adding a multiple of one row to another, then D(B) = D(A)
Let D: Mnn(R) to R be a determinant fuction, then if: -
a) B is obtained from A by multiplying a row by k then D(B) = kD(A)
b) B is obtained from A by interchanging two rows then D(B) = -D(A)
c) B is obtained from A by adding a multiple of one row to another then D(B) = D(A)
Let D: Mnn(R) to R be a determinant function. If A = (aij) is a upper of lower triangular matrix then D(A) = a11.a22.ann (diagonal entries)
There is a unique determinant function, if it exists
An nn matrix A is invertible iff the determinant ≠ 0
If E is an elementary matrix then det(EA) = det(E)det(A)
Let A,B be any two nn matrices then D(AB)=D(A)D(B)
For any nn matrix A, D(A) = D(At)
Let D: Mnn(R) to R be defined by det A) = ∑ sign(σ) a1σ(1)anσ(n). It is n linear, alternating and det(I) = 1
The determinant can be computed by the formula:
Det A) = a1jC1j + a2jC2j++anjCnj = co-factor expansion along column j
Det A) = ai1Ci1 + ai2Ci2++ainCin = co-factor expansion along row i
If A is invertible then A-1 is given by:
A-1 = 1/det(A) . adj A)
Cramers Rule If AX=B is a system of linear equations where A is an invertible nn matrix then the unique solution to the system is given by X = 1/det(A) . detA1
detAn
where Aj is a matrix obtained from A by replacing jth column by B
If A is an nn matrix the following are equivalent: -
a) λ is an eigenvalue of A
b) The homogeneous system of equations (A- λI)x = 0 has a non-zero solution
c) There is a non-zero vector x in Rn s.t Ax = λx
d) λ is a real solution to the characteristic equation det(A- λI) = 0
A matrix A is diagonalized iff A has n linearly independent eigenvectors
If v1,.,vk are eigenvectors of A corresponding to distinct eigenvalues, λ1,., λk then is a linearly independent set
If A is an nn matrix with n distinct eigenvalues then A is diagonalizable
The characteristic equation of A is (-1)N(λN (c1λN+1 + + cN)) = 0
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